python经典小游戏：24速算（案例）

import itertools
import random
import re

def solution(data):
    for i in itertools.permutations(data):
        for j in itertools.product(['+', '-', '*', '/'], repeat=3):
            li = [
                f'(({i[0]}{j[0]}{i[1]}){j[1]}{i[2]}){j[2]}{i[3]}',
                f'({i[0]}{j[0]}{i[1]}){j[1]}({i[2]}{j[2]}{i[3]})',
                f'({i[0]}{j[0]}({i[1]}{j[1]}{i[2]})){j[2]}{i[3]}',
                f'{i[0]}{j[0]}(({i[1]}{j[1]}{i[2]}){j[2]}{i[3]})',
                f'{i[0]}{j[0]}({i[1]}{j[1]}({i[2]}{j[2]}{i[3]}))'
            ]
            for k in li:
                try:
                    if eval(k) == 24:
                        print(f'{k}=24')
                        return True
                except ZeroDivisionError:
                    pass
    return False

def A2():
    poke = [str(random.randint(1, 13)), str(random.randint(1, 13)),
            str(random.randint(1, 13)), str(random.randint(1, 13))]
    poke = sorted(poke)
    print(poke)
    expr = input("输入运算式：")
    li = re.split('[\+\-\*\/\(\)]', expr)
    li = sorted(li)[-4:]
    if len(li) == 4:
        if li == poke:
            if eval(expr) == 24:
                print("正确！")
            else:
                print('错误！')
        else:
            print("检测到错误，exit")
    else:
        print("请遵守规则")

def A1():
    print("规则：\n一、输入四个1-13的数字\n二、各个数字之间要使用空格")
    print("请给机器出题：")
    topic = input().split()
    for i in topic:
        i = int(i)
        if 1 <= i <= 13:
            topic = sorted(topic)
            flag = solution(topic)
            if flag:
                print("\n得出")
                break
            elif not flag:
                print("无法得出")
                break
        else:
            print("请输入1-13的数字")
            break

while True:
    print("1.给机器出题")
    print("2.机器出题")
    print("3.退出")
    print("选择序号：")
    cmd = input()
    while True:
        if cmd == '1' or '2' or '3':
            break
        else:
            print("数据不规范，请重新输入！")
    if cmd == '1':
        A1()
    elif cmd == '2':
        A2()
    elif cmd == '3':
        break
    else:
        pass
input("按回车退出")