201403-3 命令行选项

#include <iostream>
#include <cstdio>
#include <cstring>
#include <sstream>
#include <string>
#include <vector>
using namespace std;
const int N = 30;
bool st1[N], st2[N];
string res[N];
int main()
{
  string a;
  cin >> a;
  for (int i = 0; i < a.size(); i ++ ) 
    if (i + 1 < a.size() && a[i + 1] == ':')
    {
      st2[a[i] - 'a'] = true;   //带参
      i ++;
    }
    else st1[a[i] - 'a'] = true; //不带参
  int n;
  cin >> n;
  getchar();
  for (int i = 1; i <= n; i ++ )
  {
    printf("Case %d:", i);
    getline(cin, a);
    stringstream ssin(a);
    vector<string> s;
    while (ssin >> a) s.push_back(a);
    for (int i = 0; i < N; i ++ ) res[i].clear(); //注意每次需要清空res数组
    for (int i = 1; i < s.size(); i ++ )
    {
      if (s[i][0] != '-' || s[i][1] < 'a' || s[i].size() != 2) break;     //这里break的是不合法的读入
      int k = s[i][1] - 'a';
      if (st1[k]) res[k] = "x";    //这里可以是任何东西(只要有东西就可)
      else if (st2[k] && i + 1 < s.size())
      {
        res[k] = s[i + 1];
        i ++; 
      }
      else break;
      //这里break的是合法读入中的不符合题意(如初始字符串没有'c'，但是后面读入中有'c'，'c'后面的读入是无效的)
    }
    for (int i = 0; i < N; i ++ ) 
      if (res[i].size()) 
      {
        cout << " -" << (char)(i + 'a');
        if (st2[i]) cout << ' ' << res[i];
      }
    cout << endl;
  }
  return 0;
}