题目:输入一行字符,分别统计出其中英文字母、空格、数字和其它字符的个数。
程序分析:利用while语句,条件为输入的字符不为’\n’.
方法一:
import java.util.Scanner; public class Prog7_1{ public static void main(String[] args){ System.out.print("请输入一串字符:"); Scanner scan = new Scanner(System.in); String str = scan.nextLine();//将一行字符转化为字符串 scan.close(); count(str); } //统计输入的字符数 private static void count(String str){ String E1 = "[\u4e00-\u9fa5]";//汉字 String E2 = "[a-zA-Z]"; String E3 = "[0-9]"; String E4 = "\\s";//空格 int countChinese = 0; int countLetter = 0; int countNumber = 0; int countSpace = 0; int countOther = 0; char[] array_Char = str.toCharArray();//将字符串转化为字符数组 String[] array_String = new String[array_Char.length];//汉字只能作为字符串处理 for(int i=0;i<array_Char.length;i++) array_String[i] = String.valueOf(array_Char[i]); //遍历字符串数组中的元素 for(String s:array_String){ if(s.matches(E1)) countChinese++; else if(s.matches(E2)) countLetter++; else if(s.matches(E3)) countNumber++; else if(s.matches(E4)) countSpace++; else countOther++; } System.out.println("输入的汉字个数:"+countChinese); System.out.println("输入的字母个数:"+countLetter); System.out.println("输入的数字个数:"+countNumber); System.out.println("输入的空格个数:"+countSpace); System.out.println("输入的其它字符个数:"+countSpace); } }
方法二:
import java.util.*; public class Prog7_2{ public static void main(String[] args){ System.out.println("请输入一行字符:"); Scanner scan = new Scanner(System.in); String str = scan.nextLine(); scan.close(); count(str); } //统计输入的字符 private static void count(String str){ List<String> list = new ArrayList<String>(); char[] array_Char = str.toCharArray(); for(char c:array_Char) list.add(String.valueOf(c));//将字符作为字符串添加到list表中 Collections.sort(list);//排序 for(String s:list){ int begin = list.indexOf(s); int end = list.lastIndexOf(s); //索引结束统计字符数 if(list.get(end)==s) System.out.println("字符‘"+s+"’有"+(end-begin+1)+"个"); } } }