题目
表: Warehouse
+--------------+---------+ | Column Name | Type | +--------------+---------+ | name | varchar | | product_id | int | | units | int | +--------------+---------+ (name, product_id) 是该表主键. 该表的行包含了每个仓库的所有商品信息.
表: Products
+---------------+---------+ | Column Name | Type | +---------------+---------+ | product_id | int | | product_name | varchar | | Width | int | | Length | int | | Height | int | +---------------+---------+ product_id 是该表主键. 该表的行包含了每件商品以英尺为单位的尺寸(宽度, 长度和高度)信息.
写一个 SQL 查询来报告, 每个仓库的存货量是多少立方英尺.
返回结果没有顺序要求.
查询结果如下例所示.
示例 1:
输入: Warehouse 表: +------------+--------------+-------------+ | name | product_id | units | +------------+--------------+-------------+ | LCHouse1 | 1 | 1 | | LCHouse1 | 2 | 10 | | LCHouse1 | 3 | 5 | | LCHouse2 | 1 | 2 | | LCHouse2 | 2 | 2 | | LCHouse3 | 4 | 1 | +------------+--------------+-------------+ Products 表: +------------+--------------+------------+----------+-----------+ | product_id | product_name | Width | Length | Height | +------------+--------------+------------+----------+-----------+ | 1 | LC-TV | 5 | 50 | 40 | | 2 | LC-KeyChain | 5 | 5 | 5 | | 3 | LC-Phone | 2 | 10 | 10 | | 4 | LC-T-Shirt | 4 | 10 | 20 | +------------+--------------+------------+----------+-----------+ 输出: +----------------+------------+ | WAREHOUSE_NAME | VOLUME | +----------------+------------+ | LCHouse1 | 12250 | | LCHouse2 | 20250 | | LCHouse3 | 800 | +----------------+------------+ 解释: Id为1的商品(LC-TV)的存货量为 5x50x40 = 10000 Id为2的商品(LC-KeyChain)的存货量为 5x5x5 = 125 Id为3的商品(LC-Phone)的存货量为 2x10x10 = 200 Id为4的商品(LC-T-Shirt)的存货量为 4x10x20 = 800 仓库LCHouse1: 1个单位的LC-TV + 10个单位的LC-KeyChain + 5个单位的LC-Phone. 总存货量为: 1*10000 + 10*125 + 5*200 = 12250 立方英尺 仓库LCHouse2: 2个单位的LC-TV + 2个单位的LC-KeyChain. 总存货量为: 2*10000 + 2*125 = 20250 立方英尺 仓库LCHouse3: 1个单位的LC-T-Shirt. 总存货量为: 1*800 = 800 立方英尺.
解题
select w.name as WAREHOUSE_NAME, sum(p.Width*p.Length*p.Height*w.units) as VOLUME from Warehouse as w left join Products as p on w.product_id=p.product_id group by w.name;