- 删除链表的倒数第 N 个结点
给你一个链表,删除链表的倒数第n
个结点,并且返回链表的头结点。
进阶:你能尝试使用一趟扫描实现吗?
示例 1:
输入:head = [1,2,3,4,5], n = 2
输出:[1,2,3,5]
示例 2:
输入:head = [1], n = 1
输出:[]
示例 3:
输入:head = [1,2], n = 1
输出:[1]
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode() {} * ListNode(int val) { this.val = val; } * ListNode(int val, ListNode next) { this.val = val; this.next = next; } * } */ class Solution { public ListNode removeNthFromEnd(ListNode head, int n) { ListNode hair =new ListNode(-1,head); ListNode P =head, Q =hair; while (n-- >0) { P = P.next; } while (P !=null) { P =P.next; Q =Q.next; } Q.next =Q.next.next; return hair.next; } }
C++示例: