LeetCode 36. 有效的数独

简介: 判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

题目

判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。


数字 1-9 在每一行只能出现一次。 数字 1-9 在每一列只能出现一次。 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。



上图是一个部分填充的有效的数独。


数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:
输入:
[
  ["5","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]
输出: true
示例 2:
输入:
[
  ["8","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]
输出: false
解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
     但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。

说明:


一个有效的数独(部分已被填充)不一定是可解的。 只需要根据以上规则,验证已经填入的数字是否有效即可。 给定数独序列只包含数字 1-9 和字符 '.' 。 给定数独永远是 9x9 形式的。


##解题思路 先把每行每列每个九宫格抽取出来,然后进行重复判断,可以用元组重复判断

class Solution:
    def isValidSudoku(self, board: [[str]]) -> bool:
        lines = [[] for i in range(9)] #横数组
        rows = [[] for i in range(9)] #竖数组
        block = [[] for i in range(9)]#九宫格
        for i in range(0,9):
            for j in range(0,9):
                if board[i][j] != ".":
                    lines[i].append(board[i][j])
                    rows[j].append(board[i][j])
                    block[i//3*3+j//3].append(board[i][j])
        for line in lines:
            if len(line) != len(set(line)):
                return False
        for row in rows:
            if len(row) != len(set(row)):
                return False
        for bl in block:
            if len(bl) != len(set(bl)):
                return False
        return True


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