用户选择菜单
void menu() { printf("****************************\n"); printf("******** 1.play **********\n"); printf("******** 0.exit **********\n"); printf("****************************\n"); }
用户按1进入游戏
棋盘初始化
void Itnboard(char board[ROWS][COLS], int rows, int cols,char c) { int i, j; for (i = 0; i < rows; i++) { for (j = 0; j <cols; j++) { board[i][j] = c; } } }
创建数组，并对其进行初始化
布置雷（随机布置）
void Setboard(char board[ROWS][COLS], int row, int col) { int count = Easy_count; while (count) { int x = rand() % row+1; int y = rand() % col+1; if (board[x][y] == '0') { board[x][y] = '1'; count--; } } }
用time函数产生随机值
打印棋盘
void Displayboard(char board[ROWS][COLS], int row, int col) { int i, j; for (i = 0; i <= col; i++) { printf("%d ", i); } printf("\n"); for (i = 1; i <= row; i++) { printf("%d ", i); for (j = 1; j <= col; j++) { printf("%c ", board[i][j]); } printf("\n"); } }
打印棋盘
玩家下棋
void Player(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col) { int x, y; int count = 0; while (1) { printf("请排雷：\n"); scanf("%d %d", &x, &y); if (x >= 1 && x <= 9 && y >= 1 && y <= 9) { if (board[x][y] == '0') { Openboard(show, board, x, y); Displayboard(show, ROW, COL); } else if (board[x][y] == '1') { printf("你死了\n"); break; } } else { printf("请重新输入"); } int i, j; for (i = 1; i <= row; i++) { for (j = 1; j <= col; j++) { if (show[i][j] == '*') { count++; } } } if (count == Easy_count) { printf("成功\n"); //这里的判断条件是遍历整个数组，统计雷的个数，如果雷的个数等于所剩余未排的*，说明排雷成功 break; } } }
用户输入值，并进行判断，如果该位置没有雷，我们进入展开函数
棋盘展开
void Openboard(char show[ROWS][COLS], char board[ROWS][COLS], int row, int col) { if (row >= 1 && row <= ROW && col >= 1 && col <= COL) { int count=sum(board, row, col); if (count != 0) { show[row][col] = count + '0'; } else if (show[row][col] != '_') { show[row][col] = '_'; int i = 0, j = 0; for (i = row - 1; i <= row + 1; i++) { for (j = col - 1; j <= col + 1; j++) { Openboard(show, board, i,j); } } } else { return; } } }
如果用户输入的这个位置没有雷，我们对其周围8个位置进行判断是否有雷，若有雷，我们把雷的个数显示在该位置上，若其周围8个位置没有雷并且不是下划线，我们把这个位置赋值为下划线，然后并对其8个位置进行同样的判断，如果周围没雷，而且周围的棋子也不是下划线，我们对其进行返回。
展开部分思维导图
展开函数最后一个else return 作用
这里我们show棋盘有三种情况，1.该位置是*
2.该位置是下划线
3.该位置是雷的个数
else
return；
这里是作用：如果是下划线，我们就返回上一层函数。因为如果这里不是下划线，我们会在else return 之前的语句中进行判断，并对其周围8个位置进行操作，然后再对这8个棋子各个周围8个位置进行判断并操作，如果这里是下划线，就说明由这个位置为中心的周围8个棋子已经判断过了，并且以这8个位置为中心，已经递归过了，我们不需要再进行判断，所以直接返回就行
周围雷个数判断
int sum(char board[ROWS][COLS], int x, int y) { return (board[x - 1][y - 1] + board[x - 1][y] + board[x - 1][y + 1] + board[x][y - 1] + board[x][y + 1] + board[x + 1][y - 1] + board[x + 1][y] + board[x + 1][y + 1] - 8 * '0'); }
test.c
#include"game.h" void menu() { printf("****************************\n"); printf("******** 1.play **********\n"); printf("******** 0.exit **********\n"); printf("****************************\n"); } void game() { char board[ROWS][COLS] = { 0 }; char show[ROWS][COLS] = { 0 }; Itnboard(board, ROWS, COLS,'0'); //初始化棋盘 Itnboard(show, ROWS, COLS, '*'); Setboard(board, ROW, COL); Displayboard(board, ROW, COL); Player(board, show, ROW, COL); //玩家输入 } int main() { int input=1; srand((unsigned int)time(NULL)); do{ menu(); scanf("%d", &input); switch (input) { case 1: game(); break; case 0: break; default: printf("输入错误请重新输入：\n "); } } while (input); }
game.c
#include"game.h" void Itnboard(char board[ROWS][COLS], int rows, int cols,char c) { int i, j; for (i = 0; i < rows; i++) { for (j = 0; j <cols; j++) { board[i][j] = c; } } } void Displayboard(char board[ROWS][COLS], int row, int col) { int i, j; for (i = 0; i <= col; i++) { printf("%d ", i); } printf("\n"); for (i = 1; i <= row; i++) { printf("%d ", i); for (j = 1; j <= col; j++) { printf("%c ", board[i][j]); } printf("\n"); } } void Setboard(char board[ROWS][COLS], int row, int col) { int count = Easy_count; while (count) { int x = rand() % row+1; int y = rand() % col+1; if (board[x][y] == '0') { board[x][y] = '1'; count--; } } } int sum(char board[ROWS][COLS], int x, int y) { return (board[x - 1][y - 1] + board[x - 1][y] + board[x - 1][y + 1] + board[x][y - 1] + board[x][y + 1] + board[x + 1][y - 1] + board[x + 1][y] + board[x + 1][y + 1] - 8 * '0'); } void Player(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col) { int x, y; int count = 0; while (1) { printf("请排雷：\n"); scanf("%d %d", &x, &y); if (x >= 1 && x <= 9 && y >= 1 && y <= 9) { if (board[x][y] == '0') { Openboard(show, board, x, y); Displayboard(show, ROW, COL); } else if (board[x][y] == '1') { printf("你死了\n"); break; } } else { printf("请重新输入"); } int i, j; for (i = 1; i <= row; i++) { for (j = 1; j <= col; j++) { if (show[i][j] == '*') { count++; } } } if (count == Easy_count) { printf("成功\n"); break; } } } void Openboard(char show[ROWS][COLS], char board[ROWS][COLS], int row, int col) { if (row >= 1 && row <= ROW && col >= 1 && col <= COL) { int count=sum(board, row, col); if (count != 0) { show[row][col] = count + '0'; } else if (show[row][col] != '_') { show[row][col] = '_'; int i = 0, j = 0; for (i = row - 1; i <= row + 1; i++) { for (j = col - 1; j <= col + 1; j++) { Openboard(show, board, i,j); } } } else { return; } } }
game.h
#include<stdio.h> #include<stdlib.h> #include<time.h> #define ROW 9 #define COL 9 #define ROWS ROW+2 #define COLS COL+2 #define Easy_count 10 void Itnboard(char board[ROWS][COLS], int rows, int cols,char c); void Displayboard(char board[ROWS][COLS], int row, int col); void Setboard(char board[ROWS][COLS], int row, int col); void Player(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col); void Openboard(char show[ROWS][COLS], char board[ROWS][COLS], int row, int col);
