201512-2 消除类游戏
- C++
- 总结
本题链接:201512-2 消除类游戏
本博客给出本题截图:
C++
#include <iostream> using namespace std; const int N = 35; int n, m; int g[N][N]; bool st[N][N]; int main() { cin >> n >> m; for (int i = 0; i < n; i ++ ) for (int j = 0; j < m; j ++ ) cin >> g[i][j]; for (int i = 0; i < n; i ++ ) for (int j = 0; j < m; j ++ ) { int l = j, r = j, u = i, d = i, x = g[i][j]; while (l >= 0 && g[i][l] == x) l -- ; while (r < m && g[i][r] == x) r ++ ; while (u >= 0 && g[u][j] == x) u -- ; while (d < n && g[d][j] == x) d ++ ; st[i][j] = r - l - 1 >= 3 || d - u - 1 >= 3; } for (int i = 0; i < n; i ++ ) { for (int j = 0; j < m; j ++ ) if (st[i][j]) cout << 0 << ' '; else cout << g[i][j] << ' '; cout << endl; } return 0; }
总结
水题,不解释